checkio home Non-Unique Elements
checkio home Non-Unique Elements
def checkio(data): list = data list_cnt = [] for n in list: if list.count(n) > 1: list_cnt.append(n) else: continue return list_cnt #Some hints #You can use list.count(element) method for counting. #Create new list with non-unique elements #Loop over original list if __name__ == "__main__": #These "asserts" using only for self-checking and not necessary for auto-testing assert list(checkio([1, 2, 3, 1, 3])) == [1, 3, 1, 3], "1st example" assert list(checkio([1, 2, 3, 4, 5])) == [], "2nd example" assert list(checkio([5, 5, 5, 5, 5])) == [5, 5, 5, 5, 5], "3rd example" assert list(checkio([10, 9, 10, 10, 9, 8])) == [10, 9, 10, 10, 9], "4th example" print("It is all good. Let's check it now")